Question

6-ul DAU 40 DE PUNCTE COROANA SI TOT VA ROG!​

Answer 1

Răspuns:

Explicație pas cu pas:

Answer 2

$\it n= 1+1+2+2^2+2^3+\ ...\ +2^{2018} =(1+1+2)+2^2+2^3+\ ...\ +2^{2018} =\\ \\ =(2^2+2^2)+2^3+\ ...\ +2^{2018} =(2^3+2^3) +2^4+\ ...\ +2^{2018}=\\ \\ =2^{2018}+2^{2018} =2\cdot2^{2018}=2^{2019}$

$\it u(2^{4k})=6\\ \\ u(2^{4k+1})=2\\ \\ u(2^{4k+2})=4\\ \\ u(2^{4k+3})=8\\ \\ u(2^{2019})=u(2^{2016+3})=8$