Question

-6(x-3)-3(2-x)=5-2(1-x)
Rad2x=-rad32
Rad5x-rad10=0

Answer 1

$\sqrt{2} x = - \sqrt{32} = > \sqrt{2} x = - 4 \sqrt{2} = > x = - 4$

$\sqrt{5} x - \sqrt{10} = 0 = > \sqrt{5} x = \sqrt{10} = > x = \sqrt{2} .$

$- 6(x - 3) - 3(2 - x) = 5 - 2(1 - x) = > - 6x + 18 - 6 + 3x = 5 - 2 + 2x = > - 3x + 12 = 3 + 2x = > - 3x - 2x = 3 - 12 = > - 5x = - 9 = > x = \frac{9}{5} .$