Question

627+4x[63-(17-nx3)]=835ajutor
160-447:[5-4:(8-h:1)]=1
20-[(20+p:5)x10-10]:10=0

Answer 1

Răspuns

Explicație pas cu pas:

627+4x[63-(17-nx3)]=835

4x[63-(17-nx3)] = 835 - 627 = 208

63-(17-nx3) = 208 : 4 = 52

63 - 52 = 17 - 3xn

11 = 17 - 3xn

3 x n = 17 - 11 = 6

n = 6 : 3 = 2

_________

160-447:[5-4:(8-h:1)]=1

160 - 1 = 447:[5-4:(8-h:1)]

159 = 447:[5-4:(8-h:1)]

[5-4:(8-h:1)] = 447 : 159 = 447/159

5-4:(8-h:1) = 447/159

5 - 447/159 = 4:(8-h:1)

(795 - 447)/159 = 4/(8 - h)

8 - h = 4*159 / (795 - 447)

h = 8 - 636/348 = (2784 - 636)/348 = 2148/348 = 1074/174 = 537/87 = 179/29

__________

20-[(20+p:5)x10-10]:10=0

[(20+p:5)x10-10]:10 = 20

(20+p:5)x10-10 = 200

(20+p:5)x10 = 210

(20+p:5) = 21

p:5 = 1

p = 5