Question

63-{4+5×[8×(10-x:10)] }: 2=1

Answer 1

63-{4+5×[8×(10-x:10)] }: 2=1
{4+5×[8×(10-x:10)] }: 2=63-1
{4+5×[8×(10-x:10)] }: 2=62
4+5×[8×(10-x:10)] = 62×2
4+5×[8×(10-x:10)] = 124
5×[8×(10-x:10)] = 124-4
5×[8×(10-x:10)] = 120
8×(10-x:10) = 120:5
8×(10-x:10) = 24
10-x:10 = 24:8
10-x:10 = 3
x:10 = 10-3
x:10 = 7
x = 7×10
x = 70

Answer 2

63-{4+5×[8×(10-x:10)] }:2=1
Folosesc metoda mersului invers
{4+5x[8x(10-x:10)]}:2=63-1
{4+5x[8x(10-x:10)]}:2=62
 4+5x[8x(10-x:10)] =62x2
 4+5x[8x(10-x:10)] =124
  5x[8x(10-x:10)] =124-4
  5x[8x(10-x:10)]=120
    8x(10-x:10)=120:5
    8x(10-x:10) =24
     10-x:10= 24:8
      10-x:10=3
       x:10=10-3
       x:10 =7
      x=7x10
      x=70