Question

63-{4+5×[8×(10-x:10)] }:2=1

Answer 1

$63-\Big\{4+5\times\big[8\times(10-x:10)\big] \Big\}:2=1\\ \\ -\Big\{4+5\times\big[8\times(10-x:10)\big] \Big\}:2 = 1-63 \\ \\ -\Big\{4+5\times\big[8\times(10-x:10)\big] \Big\}:2= -62 \Big|\cdot (-1)\\ \\ \Big\{4+5\times\big[8\times(10-x:10)\big] \Big\}:2 = 62 \\ \\ 4+5\times\big[8\times(10-x:10)\big] = 62\times 2 \\ \\ 4+5\times\big[8\times(10-x:10)\big] = 124\\ \\ 5\times\big[8\times(10-x:10)\big] = 124-4 \\ \\ 5\times\big[8\times(10-x:10)\big]=120\\ \\ 8\times(10-x:10) = 120:5$
$8\times(10-x:10) = 24 \\ \\ 10-x:10 = 24:8 \\ \\ 10-x:10 = 3 \\ \\ -x:10 = 3-10 \\ \\ -x:10 = -7 \\ \\ -x = -7\times 10\\ \\ -x = -70 \Big|\cdot (-1) \\ \\ x = 70$

Answer 2

63-{4+5×[8×(10-x:10)] }:2=1
Folosesc metoda mersului invers
{4+5x[8x(10-x:10)]}:2=63-1
{4+5x[8x(10-x:10)]}:2=62
 4+5x[8x(10-x:10)] =62x2
 4+5x[8x(10-x:10)] =124
  5x[8x(10-x:10)] =124-4
  5x[8x(10-x:10)]=120
    8x(10-x:10)=120:5
    8x(10-x:10) =24
     10-x:10= 24:8
      10-x:10=3
       x:10=10-3
       x:10 =7
      x=7x10
      x=70