Question

(64-32-12/a)(40-20)=9

Answer 1

[ ( 64 - 32 - 12 ) / a ] ×  ( 40 - 20 ) = 9

( 20 / a ) × 20 = 9

40  /a = 9 ⇒  9 a = 40 ⇒   a = 40 / 9 ⇒ = 4 intregi si 4/ 9 = 4,(4)

Answer 2

(64-32-12/a)(40-20)=9 in prima paranteza numitor comun a

[(64a-32a-12)/a]*20=9

(1280a-640a-240)/a=9 inmultim cu a

1280a-640a-240 =9a

1280a-640a-9a=240

631a=240⇒a=240/631