Question

{[(67X-186)x4-45]x14+290}:500=1 cum se rezolva?

Answer 1

{[(67X-186)x4-45]x14+290}:500=1
[(67X-186)x4-45]x14+290 = 500
[(67X-186)x4-45]x14 = 500-290
[(67X-186)x4-45]x14 = 210
(67X-186)x4-45 = 210 : 14
(67X-186)x4-45 = 15
(67X-186)x4 = 15+45
(67X-186)x4 = 60
67X-186 = 60:4
67X-186 = 15
67X = 15+186
67X=201
X = 201 : 67
X = 3