Question

69426-435:4:[563:3-(bx2+6x4)]+12340:5=71890

Answer 1

69426-435:4:[563:3-(bx2+6x4)]+12340:5=71890
69426-435:4:[563:3-(bx2+6x4)]+2468=71890
69426+2468-435:4:[563:3-(bx2+6x4)]=71890
71894-435:4:[563:3-(bx2+6x4)]=71890
71894-71890=435:4:[563:3-(bx2+6x4)]
4=435:4:[563:3-(bx2+6x4)]
4=435:4:[563:3-(bx2+24)]
inmultim ecuatia cu 4
16=435:[563:3-(bx2+24)]
[563:3-(bx2+24)]=436:16
eu de aici zic ca iar e scris ceva gresit
in mod normal aceste ex dau exact. te rog verifica.

Answer 2

69426-435:4[563:3(bx2+6x4)]+12340:5=71890

69246-435:(563/3-(2b+6-4))+2468=71890

69246-435:(563/3-(2b+2))+2468=71890

69246-435:(593/3-2b-2)+2468=71890

69246-435:(563-6/3-2b)+2468=71890

69246-435:(557/3-2b)+2468=71890

69246-435:557-6b/3=71890

71894-435x3/557-6b=71890

71894-1305/557-6b=71890

-1305/557-6b=71890-71894

-1305/557-6b=-4

-1305=-4(557-6b)

-1305=-2228+24b

-24b=-2226+1305

-24b=-923

b=923/24