Question

(-6x):√3=-4√15
ajutor va rog​

Answer 1

$\displaystyle\\\rm\\-\frac{6x}{\sqrt{3}} = -\frac{4}{\sqrt{15}} \implies \frac{6x}{\sqrt{3}}=\frac{4}{\sqrt{15}} \\ \\ \\6x\sqrt{15}=4\sqrt{3} \implies 6x = \frac{4\sqrt{3}}{\sqrt{15}} = \frac{4\sqrt{45}}{15} \\ \\ \\x = \frac{4\sqrt{45}}{15 \times 6 } = \frac{4\sqrt{45}}{75} = \frac{2\sqrt{5}}{15}$