Question

6x[(ax3:2-9):9+8]+40:10=94

Answer 1

6 × [ ( a × 3 : 2 - 9 ) : 9 + 8 ] + 40 : 10 = 94

6 × [ ( a × 3 : 2 - 9 ) : 9 + 8 ] + 4 = 94

6 × [ ( a × 3 : 2 - 9 ) : 9 + 8 ] = 94 - 4

6 × [ ( a × 3 : 2 - 9 ) : 9 + 8 ] = 90

[ ( a × 3 : 2 - 9 ) : 9 + 8 ] = 90 : 6

[ ( a × 3 : 2 - 9 ) : 9 + 8 ] = 15

[ ( a × 3 : 2 - 9 ) : 9 ] = 15 - 8

[ ( a × 3 : 2 - 9 ) : 9 ] = 7

a × 3 : 2 - 9 = 7 × 9

a × 3 : 2 - 9 = 63

a × 3 : 2 = 63 + 9

a × 3 : 2 = 72

a × 3 = 72 × 2

a × 3 = 144

a = 144 : 3

a = 48

Answer 2

Răspuns

Explicație pas cu pas:

6 x [ ( a x 3 : 2 - 9 ) : 9 + 8 ] + 40 : 10 = 94

6 x [ ( a x 3 : 2 - 9 ) : 9 + 8 ] + 4 = 94

6 x [ ( a x 3 : 2 - 9 ) : 9 + 8 ] = 94 - 4

6 x [ ( a x 3 : 2 - 9 ) : 9 + 8 ] = 90

( a x 3 : 2 - 9 ) : 9 + 8 = 90 : 6

( a x 3 : 2 - 9 ) : 9 + 8 = 15

( a x 3 : 2 - 9 ) : 9 = 15 - 8

a x 3 : 2 - 9 = 7 × 9

a x 3 : 2 - 9 = 63

a x 3 : 2 = 63 + 9

a × 3 : 2 = 72

a × 3 = 72 × 2

a × 3 = 144

a = 144 : 3

a = 48 → numarul, aflat prin metoda mersului invers