Question

7,(15)+2,(18)-5,(23)+11,(20)= ajutatima

Answer 1

[tex] \frac{715-7}{99} + \frac{218-2}{99} - \frac{523-5}{99} + \frac{1120-11}{99} = \frac{708}{99}+ \frac{216}{99} - \frac{518}{99} + \frac{1109}{99} = [/tex]
[tex] \frac{924}{99} - \frac{518}{99} + \frac{1109}{99} = \frac{406}{99} + \frac{1109}{99} = \frac{1515}{99} = \frac{505}{33} [/tex]

Answer 2

$\displaystyle 7,(15)+2,(18)-5,(23)+11,(20)= \\ \\ = \frac{715-7}{99} + \frac{218-2}{99} - \frac{523-5}{99} + \frac{1120-11}{99} = \\ \\ = \frac{708}{99} + \frac{216}{99} - \frac{518}{99} + \frac{1109}{99} = \frac{924}{99} - \frac{518}{99} + \frac{1109}{99} = \\ \\ = \frac{406}{99} + \frac{1109}{99} = \frac{1515}{99} ^{(3} = \frac{505}{33}$