Question

7/3-2,(3) pls urgent​

Answer 1

$\it \dfrac{7}{3} - 2,(3)=\\\\\\\dfrac{7}{3} - \dfrac{23-2}{9}=\\\\\\\dfrac{7}{3} - \dfrac{\not21}{\not9}=\\\\\\\dfrac{7}{3} - \dfrac{7}{3}= \boxed {\it 0}$

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Answer 2

7/3-2,(3)=

=2,(3)-2,(3)=0