Question

(7/32+1/40+6/96):71/480

Answer 1

$\left( {\dfrac{^{15)}7}{\ 32}} +\dfrac{^{12)} 1}{\ 40}+\dfrac{^{5)}6}{\ 96}\right):\dfrac{71}{480}=\dfrac{105+12+30}{480}\cdot\dfrac{480}{71}$

Se efectueaza adunarile si se simplifica prin 480