Question

[(7 350:35+124 569:9-124×56-107)×3]: (11×51 +13×12+283). (Etapa judeteand, 1985, Bihor)​

Answer 1

$\bf \purple{\underline{21}}$

Explicație pas cu pas:

Respectăm ordinea efectuării operațiilor

$\bf \big[(7 \: 350:35+124 \: 569:9-124 \cdot 56-107) \cdot3 \big]: (11 \cdot 51 +13 \cdot12+283) =$

$\bf \big[(210+124 \: 569:9-124 \cdot 56-107) \cdot3 \big]: (11 \cdot 51 +13 \cdot12+283) =$

$\bf \big[(210+13 \: 841-124 \cdot 56-107) \cdot3 \big]: (11 \cdot 51 +13 \cdot12+283) =$

$\bf \big[(210+13 \: 841-6 \: 944-107) \cdot3 \big]: (11 \cdot 51 +13 \cdot12+283) =$

$\bf \big[(14 \: 051-6 \: 944-107) \cdot3 \big]: (11 \cdot 51 +13 \cdot12+283) =$

$\bf \big[(7 \: 107-107) \cdot3 \big]: (11 \cdot 51 +13 \cdot12+283) =$

$\bf \big(7 \: 000\cdot3 \big): (561 +13 \cdot12+283) =$

$\bf 21\: 000: (561 +156+283) =$

$\bf 21\: 000: 1000 = \purple{\underline{21}}$

==pav38==

Baftă multă !