Question

{7+7*[7+3*(5+45:3-15)]}-161​

Answer 1

$7+7\left[7+3\left(5+45\div \:3-15\right)\right]-161 =$

$[7+3\left(5+45\div \:3-15\right)\right/]= 7+3\left(5+45\div \:3-15\right) = 7+3\cdot \:5 =7+15 =22$

$7+7\cdot \:22-161 =$

$7+154-161 = 0$