Question

( 7 la putere 11) la puterea 13 x (7 la puterea 13)la puterea 7 : (7 la puterea 18)la puterea 13 x 7 la puterea 2 + 1 la puterea 2017 - 2 la puterea 1 x 5 la puterea 2

Answer 1

$(((7^{11})^{13}*(7^{13})^7):(7^{18})^{13})*7^2+1^{2017}-2^1*5^2=\\\\(7^{143}*7^{91}):7^{234})*7^2+1-2*25 =\\\\(7^{234}:7^{234})*7^2+1-50=\\1*49-49 = 49-49 = 0$