Question

[(7 la puterea 2+7 la puterea 0)totu la puterea 2 :10 la puterea 2 -2 la puterea 4]totu la puterea 7:3 la puterea 13

Answer 1

$[(7^2+7^0)^2:10^2-2^4]^7:3^{13}=[(49+1)^2:10^2-2^4]^7:3^{13}=\\=[50^2:10^2-2^4]^7:3^{13}=[2500:100-16]^7:3^{13}=9^7:3^{13}=(3^2)^7:3^{13}\\=3^{14}:3^{13}=3$