Question

(7 la puterea 2004+7 la puterea 2002+ 7 la puterea 2003)/(7 la puterea 2+ 824/103)=

Answer 1

Sper că te-am ajutat!.............

Answer 2

$( {7}^{2004} + {7}^{2002} + {7}^{2003} ) \div ( {7}^{2} + \frac{824}{163})$

$( {7}^{2} + 1 + 7) \times {7}^{2002} \div (49 + \frac{824}{163} )$

$(49 + 1 + 7) \times {7}^{2002} \div \frac{8811}{163}$

$57 \times {7}^{2002} \times \frac{163}{8811}$

$19 \times {7}^{2002} \times \frac{163}{2937}$

$\frac{3097 \times {7}^{2002} }{2937}$

Sper ca ti-am fost de folos. Succes!!!