Question

(7 la puterea2-3la puterea2):2la puterea2+7la puterea2-1la puterea2004+0la puterea2005

Answer 1

$4^{2} : 2^{2} + 7^{2} - 1^{2004} + 0^{2005} = 2^{2} +49 +1+1=4+49+1+1 =52$