Question

7. Ordonați crescător:

a) 2^ 45 ;3^ 27 ;4^ 18 ;

d) 5^ 15 ;3^ 35 ;12^ 10 ;

b) 2^ 56 ;5^ 24 ;3^ 32 ;

e) 9^ 33 ;3^ 52 ;27^ 19 ;

c) 5^ 44 ;3^ 66 ;2^ 110 ,

f) 5 ^ 44 / (25 ^ 29) / (625 ^ 11)
Va rogg cât de repede se poate

Answer 1

Răspuns:

Explicație pas cu pas:

a) 2^ 45= (2^5)^9= 32^9 ;3^ 27= (3^3)^9=27^9 ;4^ 18= 2^36= (2^4)^9= 16^9

ordonam crescator: 4^ 18; 3^ 27;  2^ 45

d) 5^ 15= (5^3)^5 = 125^5 ;3^ 35= (3^7)^5= 2187^5 ;12^ 10= (12^2)^5=144^5

ordonam crescator: 5^ 15; 12^ 10; 3^ 35

b) 2^ 56= (2^7)^8= 128^8  ;5^ 24 = (5^3)^8= 125^8 ;3^ 32= (3^4)^8= 81^8 ;

ordonam crescator: 3^ 32; 5^ 24; 2^ 56

e) 9^ 33=(3^2)^33= 3^66; 3^ 52 ;27^ 19=(3^3)^19= 3^57 ;

ordonam crescator: 3^ 52 ; 27^ 19; 9^ 33;

c) 5^ 44= (5^4)^11= 625^11 ;3^ 66= (3^6)^11= 729^11 ;2^ 110= (2^10)^11 =1024^11

ordonam crescator: 5^ 44; 3^ 66; 2^ 110

f) 5 ^ 44 ; (25 ^ 29)= (5^2)^29= 5^58 / (625 ^ 11)=(5^4)11= 5^44

ordonam crescator: 5 ^ 44=625 ^ 11; 25 ^ 29