Question

7 radical din 3-4 radical din 3•2

Answer 1

$7 \sqrt{3} - 4 \sqrt{3 \times 2} = 7 \sqrt{3} - 4 \sqrt{6} \\ \\ 7 \sqrt{3} - 4 \sqrt{3} \times 2 = 7 \sqrt{3} - 8 \sqrt{3} = - \sqrt{3}$