Question

7 Se ştie că a = 11 şi b+c= 8. Calculați: VĂ ROG MĂ OMOARĂ DOAMNA​

Answer 1

Răspuns:

A) A(B + C) = 11 * 8 = 88

B) 2A + 3(B + C) = 2 * 11 + 3 * 8 = 22 + 24 = 46

C) 10A + 9(B + C) = 10 * 11 + 9 * 8 = 110 + 72 = 182

D) A(B + C) + 25 = 11 * 8 + 25 = 88 + 25 = 113

E)A(B + C) - 34 = 11 * 8 - 34 = 88 - 34 = 54

F) 7(B + C) + 9A = 7 * 8 + 9 * 11 = 56 + 99 = 155

Answer 2

$a. \: a + b + a + c = a(b + c) = 11 \times 8 = \bf 88$

$b. \: 2a + 3b + 3c = 2 \times 11 + 3(b + c) = 22 + 3 \times 8 = 22 + 16 =\bf 38$

$c. \: 10a + 9b + 9c = 10 \times 11 + 9(b + c) = 110 + 9 \times 8 = 110 + 72 =\bf 182$

$d. \: ab + ac + 25 = a(b + c) + 25 = 11 \times 8 + 25 = 88 + 25 =\bf 113$

$e. \: ab + ac - 34 = a(b + c) - 34 = 11 \times 8 - 34 = 88 - 34 =\bf 54$

$f. \: 7b + 7c + 9a = 7(b + c) + 9 \times 11 = 7 + 8 + 99 =\bf 114$

$g. \: 11b + 11c - 6a = 11(b + c) - 6 \times 11 = 11 \times 8 - 66 = 88 - 66 =\bf 22$

$h. \: 3a - 3b - 3c = 3 [ - (a + b + c)] = 3 [ - (11 + 8)] = 3( - 19) = \bf - 57$

$i. \: 11b + ac = 11b + 11c = 11(b + c) = 11 \times 8 = \bf 88$