Question

73 g HCL reactioneaza cu o solutie de AgNo3. Calculati cantitatea de precipitatii obtinuta in g/mol. VA ROG. URGENT

Answer 1

M,HCl= 36,5g/mol

calculez moli de acid in masa data

niu(mol)= m/M= 73/36,5mol= 2molHCl

calculez moli si masa AgCl din ecuatia chimica

1mol...............................................1mol

HCl    +  AgNO3----> HNO3 + AgCl↓

2mol....................................................x=2mol AgCl

m= niuxM= 2X(108gAg +35,5gCl)=......................calculeaza