Question

√75-√3(4√27+5)= CALCULATI VA ROG a)[9*(-11 pe 35)⁰-8,8] la puterea - 2=

Answer 1

Răspuns:

Explicație pas cu pas:

$\sqrt{75} - \sqrt{3} (4\sqrt{27} +5)=\\=\sqrt{25*3} - 4\sqrt{3}\sqrt{27} -5\sqrt{3}=\\=\sqrt{25}\sqrt{3} - 4\sqrt{3*27} -5\sqrt{3}=\\=5\sqrt{3} - 4\sqrt{81} -5\sqrt{3}=\\=5\sqrt{3} -5\sqrt{3} - 4*9 =\\=36.$

$[9*(-\frac{11}{35} )^{0} -8,8]^{-2} = \\=(9*1 -8,8)^{-2} = \\=(9-8,8)^{-2} = \\=(0,2)^{-2} = \\\\=(\frac{2}{10} )^{-2} = \\\\=(\frac{1}{5} )^{-2} = \\\\=\frac{1}{(\frac{1}{5})^{2}} = \\\\=(\frac{1}{\frac{1}{5}})^{2} =\\ \\= 5^{2} = \\=25$