Question

76+77+78+….+233+234
va rog ajutorr

Answer 1

Folosim suma lui Gauss:

$1 + 2 + 3 + 4 + ... + 232 + 233 + 234 = \frac{234 \times (234 + 1)}{2} = 117 \times 235 = 27495$

$1 + 2 + 3 + ... + 74 + 75 = \frac{75 \times (75 + 1)}{2} = 75 \times 38 = 2850$

76+77+...+234 = (1+2+3+...+233+234) - (1+2+...+74+75) = 27495 - 2850 = 24645