Question

7A.va rog frumos!
dau 100puncte și coroană
va rog frumos repede!​

Answer 1

$\frac{6}{\sqrt{3} } + 2\sqrt{3} - \sqrt{27} \\= \frac{6\sqrt{3} }{3} + 2\sqrt{3} - 3\sqrt{3} \\= \frac{6\sqrt{3} }{3} + \frac{6\sqrt{3} }{3} - \frac{9\sqrt{3} }{3} \\= \frac{12\sqrt{3} }{3} - \frac{9\sqrt{3} }{3} \\= \frac{3\sqrt{3} }{3} \\= \sqrt{3}$

Answer 2

Răspuns:

$a) \frac{\sqrt{3} /6}{\sqrt{3}} +2\sqrt{3} -\sqrt{27} = \frac{6\sqrt{3} }{3} +2\sqrt{3}-3\sqrt{3} = \frac{6\sqrt{3} }{3} -3/1\sqrt{3} = \frac{6\sqrt{3} -3\sqrt{3} }{3} = \frac{3\sqrt{3} }{3} = \sqrt{3}$

$b) \frac{\sqrt{2} /10}{\sqrt{2} } +\frac{\sqrt{6}/12\sqrt{2}}{\sqrt{6}} -2\sqrt{50} =\frac{10\sqrt{2} }{2} +\frac{12\sqrt{12} }{6} -2*5\sqrt{2}= 5\sqrt{2} +2*2\sqrt{3}-10\sqrt{5} =5\sqrt{2} +4\sqrt{3}-10\sqrt{5}$

$c) \frac{\sqrt{2}/5}{\sqrt{2} }+\frac{\sqrt{2}/7}{3\sqrt{2}} -\frac{\sqrt{6} /2\sqrt{3} }{\sqrt{6}} =\frac{3/5\sqrt{2} }{2}+\frac{7\sqrt{2} }{6} -\frac{2*3\sqrt{2} }{6} =\frac{15\sqrt{2}+7\sqrt{2}-6\sqrt{2} }{6} =\frac{16\sqrt{2} }{6} =\frac{8\sqrt{2} }{3}$

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