Question

[7supra36 - 1supra 46•(5întreg2supra3 - 3 întreg3supra4)]:1 întreg 3 supra8.

Answer 1

Răspuns:

{7/36-1/46×[5×3+2)/3-(3×4+3)/4]}:(1×8+3)/8=

[7/36-1/46×(⁴⁾17/3-³⁾15/4)]:11/8=

[7/36-1/46×(68/12-45/12)]:11/8=

(7/36-1/46×23/12)×8/11=

(²⁾7/36-³⁾1/24)×8/11=

(14/72-3/72)×8/11=

11/72×8/11=

1/9