Question

7X-3 (x+4) = 2(x+3) + 9
2[6(3x+2) -23]=86
3[14+7(x+1) ]+5=110
2×[7(2x+1) -11]+16=36
5×[6(2x+5) -12]-140=10
va rooog mult de tot! am 20 de exerciții de terminat până maine​

Answer 1

a)

$7x - 3(x + 4) = 2(x + 3) + 9$

$7x - 3x - 12 = 2x + 6 + 9$

$4x - 12 = 2x + 15$

$4x - 2x = 15 + 12$

$2x = 27$

$x = \frac{27}{2}$

b)

$2(6(3x + 2) - 23) = 86$

$6 (3x + 2) - 23 = 43$

$18x + 12 - 23 = 43$

$18x - 11 = 43$

$18x = 43 + 11$

$18x = 54$

$x = 3$

c)

$(14 + 7(x + 1)) + 5 = 110$

$(14 + 7x + 7) + 5 = 110$

$(21 + 7x) + 5 = 110$

$21 + 7x + 5 = 110$

$26 + 7x = 110$

$7x = 110 - 26$

$7x = 84$

$x = 12$

d)

$2 \times (7(2x + 1) - 11) + 16 = 36$

$2 \times (14x + 7 - 11) +1 6 = 36$

$2 \times (14x - 4) + 16 = 36$

$28x - 8 + 16 = 36$

$28x + 8 = 36$

$28x = 36 - 8$

$28x = 28$

$x = 1$

e)

$5 \times (6(2x + 5) - 12) - 140 = 10$

$5 \times (12x + 30 - 12) - 140 = 10$

$5 \times (12x + 18) - 140 = 10$

$60x + 90 - 140 = 10$

$60x - 50 = 10$

$60x = 10 - + 50$

$60x = 60$

$x = 1$