Question

8^0+1^3+0^4+12^1+8^2
3^27×5^3÷5^28
(3^8)÷3^37
2^30÷2^25+2^4^0-2^1×[128÷2^5+2^3:(2×2^4-24^1)]

Answer 1

8^0+1^3+0^4+12^1+8^2=
1+1+0+12+64=
14+64=78

3^27×5^3:5^28=
7×125÷3=
875:3=291

(3^8):3^37=
6:4=4 rest 2

2^30÷2^25+2^4^0-2^1×[128:2^5+2^3:(2×2^4-24^1)]=
1:1+1-2×[128:32+8:(2×16-24)]=
1:1+1-2×[4+8:(32-24)]=
1:1+1-2×[4+8:8]
1:1+1-2×[4+1]
1:1+1-2×5
1+1-10
2-10= -8


SPER CA TE-AM AJUTAT