Question

8×13-8×8÷{13-4×3÷[2×11-1×5×(19×2-2×2×x)]+2×2}= 100+0÷99 Dau coroana primului corect raspuns!

Answer 1

Răspuns:

Explicație pas cu pas:

8×13 - 8×8 ÷ {13 - 4×3 ÷ [2×11 - 1×5×(19×2 - 2×2×x)] + 2×2}= 100 + 0÷99

104 - 64 ÷ {13 - 12 ÷ [22 - 5×(38 - 4×x)] + 4}= 100 + 0

64 ÷ {13 - 12 ÷ [22 - 5×(38 - 4×x)] + 4} = 104 - 100 = 4

13 - 12 ÷ [22 - 5×(38 - 4×x)] + 4 = 64 : 4 = 16

12 ÷ [22 - 5×(38 - 4×x)] = 13 + 4 - 16 = 1

22 - 5×(38 - 4×x) = 12 : 1 = 12

5×(38 - 4×x) = 22 - 12 = 10

38 - 4×x = 10 : 5 = 2

4×x = 38 - 2 = 36

x = 36 : 4 = 9