Question

(8-2√2)•(3√2-4) pls ajutor ​

Answer 1

2

$2 \sqrt{2} = {2}^{2} \times 2 = 4 \times 2 = 8$

$(8 - 8) \times (3 \sqrt{2 } - 4)$

$3 \sqrt{2} = {3}^{2} \times 2 = 9 \times 2 = 18 - 4 = 14$

$0 \times 14 = 0$

Answer 2

(8-2√2)×(3√2-4)=

=24√2-32-12+8√2=32√2-44