Question

√8+2
______ = ?
√8-2

Answer 1

$\frac{ \sqrt{8} +2}{ \sqrt{8}-2} = \frac{( \sqrt{8} +2)( \sqrt{8}+2 )}{ \sqrt{ 8^{2}- 2^{2} } } = \frac{ \sqrt{64} + 2\sqrt{8} + 2\sqrt{8} + \sqrt{64} }{8-4} = \frac{8+8+ 2\sqrt{8} + 2\sqrt{8}}{4} = \frac{16+ 4\sqrt{8} }{4} =$=$\frac{16}{4} + \frac{4 \sqrt{8} }{4} =4+ \sqrt{8}$