Question

8+2 x [2^6 : 4^2 +2^3 x (16^2 : 8^2 - 64 :2^5)]va rog repede!!!!​

Answer 1

Răspuns

$8 + 2( {2}^{6} \div {4}^{2} + {2}^{3} \times ( {16}^{2} \div {8}^{2} - 64 \div {2}^{5} ))$

$8 + 2( {2}^{6} \div {2}^{4} + {2}^{3} \times ( {2}^{8} \div {2}^{6} - {2}^{6} \div {2}^{5} ))$

$8 + 2( {2}^{2} + {2}^{3} \times ( {2}^{2} - 2))$

$8 + 2(4 + {2}^{3} \times (4 - 2))$

$8 + 2(4 + 2^{3} \times 2$

$8 + 2(4 + {2}^{4} )$

$8 + 2(4 + 16)$

$8 + 2 \times 20$

$8 + 40$

$48$

Sper că te-am ajutat:)