Question

8(4sqrt(2) - 2sqrt(3)) - (18/(sqrt(18)) + 27/(sqrt(27))) * 3sqrt(6) - (5/(sqrt(75)) - 10/(sqrt(9))) > 3sqrt(6)​

Answer 1

Explicație pas cu pas:

$8(4 \sqrt{2} - 2 \sqrt{3}) - \bigg( \dfrac{18}{ \sqrt{18} } + \dfrac{27}{ \sqrt{27} } \bigg) \cdot 3 \sqrt{6} - \bigg(\dfrac{5}{ \sqrt{75} } - \dfrac{10}{ \sqrt{9} } \bigg) \cdot 3 \sqrt{6} =$

$= 8(4 \sqrt{2} - 2 \sqrt{3}) - \bigg( \dfrac{18}{ 3\sqrt{2} } + \dfrac{27}{ 3\sqrt{3} } \bigg) \cdot 3 \sqrt{6} - \bigg(\dfrac{5}{5 \sqrt{3} } - \dfrac{10}{3} \bigg) \cdot 3 \sqrt{6}$

$= 32 \sqrt{2} - 16 \sqrt{3} - \bigg(18 \sqrt{3} + 27 \sqrt{2} \bigg) - \bigg(3 \sqrt{2} - 10 \sqrt{6} \bigg)$

$= 32 \sqrt{2} - 16 \sqrt{3} - 18 \sqrt{3} - 27 \sqrt{2} - 3 \sqrt{2} + 10 \sqrt{6}$

$= 2 \sqrt{2} - 34 \sqrt{3} + 10 \sqrt{6}$