Question

(8/9+64/81+2/3)×3/4÷128/243×16/27

Answer 1

$( \frac{72}{81} + \frac{64}{81} + \frac{54}{81} )* \frac{3}{4} * \frac{243}{128} * \frac{16}{27}$
$\frac{190}{81}* \frac{3}{4} * \frac{243}{128} * \frac{16}{27}$
simplificam
$\frac{190}{1} * \frac{1}{4} * \frac{1}{128} * \frac{16}{3}$
$\frac{190}{4} * \frac{1}{24} = \frac{95}{48}$