Question

8. Adevărat sau fals?
$3x - 2 \leqslant 0 < = > 2 - 3x \geqslant 0 \\ x {}^{2} + 1 > 0 < = > (x + 1) {}^{2} < 0$
va rog frumos dau corona​

Answer 1

1 ADEVARAT

$3x - 2 \leqslant 0 | \times ( - 1) \\ - 3x + 2 \geqslant 0 \\ 2 - 3x \geqslant 0$

2 FALS

$(x + 1) {}^{2} = {x}^{2} + 2x + {1}^{2}$