Question

8. Rezolvaţi ecuatiile în multimea numerelor reale: a) 4(x + 2) - 3x = -17; b) 6(x + 5) - 3x = 21; c) 11 - 3(r + 5) = 2x + 1: d) 32 - 7(x - 5) = 3(x - 1); c) 4(x - 6) + 2x = 18; 1) 4(x + 7) - 15 = 3x: g) 14 - 8(x + 3) = 2x, h) 6(x + 3) - 4 - 2x - 42; i) 6(x -- 4) + 44 = 4(2x + 1) + 2x, j) 5(2x - 3) - 4x = 3(x - 8) + 63; k) 3(x + 2)-8=2(4x + 3) - 3x; 1) 4(3x + 2) + 3(2x + 3) = 7(2x + 5) + 28; m) 4(x + 5) - 5(x + 3) = x-5; n) 2(x + 3) - 3(2x + 1) = 8(2x - 1) - 9 0) 3(2x + 3) - 2(3x + 2) = -3(x + 2) + 2; p) -3x + 5- 4(x - 1) = -2(x + 1) - 24; T) x - 15+ 3(x + 1) = 5(x - 2) +11; s) 5(x + 2) - 2(2x + 3) = 34 - 5x. --3=5; +7=-35; 5x + 11;​

Answer 1

Răspuns:

+ 5) - 3x = 21; c) 11 - 3(r + 5) = 2x + 1: d) 32 - 7(x - 5) = 3(x - 1); c) 4(x - 6) + 2x = 18; 1) 4(x + 7) - 15 = 3x: g) 14 - 8(x + 3) = 2x, h) 6(x + 3) - 4 - 2x - 42; i) 6(x -- 4) + 44 = 4(2x + 1) + 2x, j) 5(2x - 3) - 4x = 3(x - 8) + 63; k) 3(x + 2)-8=2(4x + 3) - 3x; 1) 4(3x + 2) + 3(2x + 3) = 7(2x + 5) + 28; m)=12957

Explicație pas cu pas: