Question

{8 supra35+[(3supra2-33supra35)+(3supra14-2supra25)-(2-12supra7+5supra14)]}x3intregi 1supra3

Answer 1

{8/35+[(3/2-33/35)+(3/14-2/25)-(2-12/7+5/14)]}x10/3=
{8/35+[(35x3-33x2)/70+(25x3-2x14)/350-(14x2-12x2+5x2)/14]}x10/3=
{8/35+[(105-66)/70+(75-28)/350-(28-24+10)14]}x10/3=
{8/35+[(39/70+47/350-14/14)]}x10/3=
{8/35+[(39/70+47/350-1)]}x10/3=
{8/35+[(39x5+47-350)/350)]}x10/3=
{8/35+[(195+47-350)/350)]}x10/3=
(8/35-108/350)x10/3=
(8x10-108)/350x10/3=
(80-108)350x10/3=
-38/350x10/3=
-28/105

Answer 2

Sigur e corect cum l-ai scris(2-12 supra 7+5 supra 14)Aici e corect?Știu sa îl rezolv dar aici nu înțeleg!