Question

84, va rog mult ! Mulțumesc

Answer 1

n1 moli    H2C=CH-CH3 +5[O] ⇒ CH3-COOH + CO2 + H2O
n2 moli    H2C=CH-CH2-CH3 +5 [O] ⇒CH3-CH2-COOH + CO2+ H2O
n3 moli    H3C-CH=CH-CH3 + 4[O] ⇒ 2CH3-COOH
n4 moli    H2C=C(CH3)-CH3 + 4[O] ⇒ CH3-CO-CH3 + CO2 + H2O
K2Cr2O7 + 4H2SO4 ⇒ K2SO4 + Cr(SO4)3 + 4H2O + 3[O]
(n1 + 2n3)/6 = (n1+n2 + n4)/5 = n4/1 = n2/1 =( 2n1+2n2+2n3+2n4)/13 = 2n/13
n2 = n4 = 2n/13;  n1 + 2n3 = 12n/13   n1 + 2n2 = 10n/13 ⇒ n3 - n2 = n/13 ⇒
 n3 = 3n/13   n1 = 7n/13
n1/n1K2Cr2O7 = 5/3   n1K2Cr2O7 = 0,6n1 ; n2K2Cr2O7=0,6n2  
n3/n3K2Cr2O7 = 4/3   n3K2Cr2O7 = 0,75n3; n4K2Cr2O7 = 0,75n4   
0,6·7n/13 + 0,6·2n/13 + 0,75n·3n/13 + 0,75·2n/13 = 30
(4,2 + 1,2 + 2,25 + 1,5)n = 390     n = 390/9,15 = 39000/915 = 2600/61
m produsi = (n1+2n3)·60 + n4·58 + n2·74 =
= [(4,2+2,25)·60+1,5·58+1,2·74]·2600/61 = (387 + 87 + 88,8)·2600/61 =
= ≈24kg
n-am siguranta ca n-am gresit la calcule........ urmariti mersul rezolvarii ...