Question

(8x la puterea 4 -40x la puterea 3 + 28x la puterea 2) : (4x la puterea2 ) -2 (x+2) . 

Answer 1

 [tex] \frac{deimpartitul}{impartitorul}=\frac{8x^4-40x^3+28x^2}{4x^2}=\frac{4x^2(2x^2-10x+7)}{4x^2}\;=\;2x^2-10x+7\;;\\
expresia\;devine:\\
...\;2x^2-10x+7\,\;-\;\,2x-4=\;2x^2-12x+3\;; [/tex]