Question

(9+3^100:3^98+3^45:3^43):3^2

Answer 1

$(9 + {3}^{100} \div {3}^{98} + {3}^{45} \div {3}^{43} ) \div {3}^{2} = (9 + {3}^{2} + {3}^{2} ) \div {3}^{2} = 3 \times {3}^{2} \div {3}^{2} = 3$