Question

(9+3la puterea 4 :9 la puterea 2 ) :10+81×82:41:3la puterea 3 -(2013la puterea 2014)la puterea 0

Answer 1

9^2=(3^2)^2=3^4

(9+3^4:3^4):10+6642:41:27-1= (9+1):10+162:27-1= 10:10+6-1= 1+6-1= 6

Answer 2

$(9 + {3}^{4} \div {9}^{2} ) \div 10 + 81 \times 82 \div 41 \div {3}^{3} - {( {2013}^{2014} )}^{0}$

$= [9 + {3}^{4} \div { ({3}^{2}) }^{2} ]\div 10 + 6642 \div 41 \div 27 - {2013}^{2014 \times 0}$

$= (9 + {3}^{4} \div {3}^{2 \times 2} ) \div 10 + 162 \div 27 - {2013}^{0}$

$= (9 + {3}^{4} \div {3}^{4} ) \div 10 + 6 - 1$

$= (9 + 1) \div 10 + 6 - 1$

$= 10 \div 10 + 6 - 1$

$= 1 + 6 - 1$

$= 7 - 1$

$= 6$