Question

9,4 g fenol reactioneaza cu o solutie de acid azotic de concentratie 30%. Se cere:
a) Masa de acid picric obtinut
b) Masa de solutie de acid azotic necesara

Answer 1

C6H5-OH + 3 HNO3 = C6H2-OH(NO2)3 + 3 H2O
M fenol = 6*12+6*1+16 = 94
M HNO3 = 1+14+3*16 = 63
M acid picric = 6*12+3*1+3*14+7*16 = 229
94 g fenol.....3*63 g HNO3.....229 g acid picric
9,4 g fenoo............x..........................y
x = 18,9 g HNO3
y = 22,9 g acid picric
c = md/ms * 100
ms = md/c*100 = 18,9/30 * 100 = 63 g soluție HNO3 30%