Question

9(4x+1)²-16(2x+3)²=?

(4x-3)²-(2x+1)²=?

Answer 1

9(4x+1)²-16(2x+3)² =
= [ 3 ( 4x + 1 ) - 4(2x +3 ) ] × [ 3 ( 4x + 1 ) + 4( 2x + 3 ) ] =
= ( 12x + 3 - 8x - 12 ) × ( 12x + 3 + 8x + 12 ) =
= ( 4x + 3 - 12 ) × ( 12x + 3 + 8x + 12 ) =
= ( 4x - 9 ) × ( 12x + 3 + 8x + 12 ) =
= ( 4x - 9 ) × ( 20x + 15 ) =
= ( 4x - 9 ) × 5(4x + 3 ) =
= 5(4x - 9 )( 4x + 3 )


(4x-3)²-(2x+1)² = 
= [ 4x - 3 - ( 2x + 1 ) ] × [ 4x - 3 + ( 2x + 1 ) ] =
= ( 4x - 3 - 2x - 1 ) × ( 4x - 3 + 2x + 1 ) =
= ( 2x - 4 ) × ( 6x - 2 ) =
= 2( x - 2 ) × 2( 3x - 1 ) =
= 2 × 2( x - 2 ) × ( 3x - 1 ) =
= 4( x - 2 )( 3x - 1 ) 

Answer 2

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