Question

9^(6x) + 81^(3x) + 27^(4x) = 243^(5)
X=??

Answer 1

=  (3^2)^6x  + (3^4)^3x + (3^3)^4x = (3^5)^5

=>3^12x + 3^12x + 3^12x = 3^25

=> 3^12X × ( 1+1+1)= 3^25

=> 3^12X × 3= 3^25

3^12x= 3^25 : 3 = 3^24

(3^X)^12= 3^24

(3^X)^12= (3^2)^12

3^X = 3^2

X= 2