Question

9×{8+7×[6+5×(4+3×(2+1))]}÷(1+2+3+...+9)
ma puteti ajuta va rog​

Answer 1

Răspuns:

101

Explicație pas cu pas:

9×{8+7×[6+5×(4+3×(2+1))]}÷(1+2+3+...+9)=

=9×{8+7×[6+5×(4+3×3)]}÷(3+3+4+5+6+7+8+9)

=9×{8+7×[6+5×(4+9)]}÷(6+4+5+6+7+8+9)

=9×[8+7×(6+5×13)]÷(10+5+6+7+8+9)

=9×[8+7×(6+65)]÷(15+6+7+8+9)

=9×(8+7×71)÷(21+7+8+9)

=9×(8+497)÷(28+8+9)

=9×(8+497)÷(28+8+9)

=9×505÷(36+9)

=9×505÷45

=505÷5

=101