Question

9. Calculează:
@ (3)*(3)-(3)*; b) (12):14+
5) [1+(?)*].[1-(3)].[1-6].
​

Answer 1

Răspuns:

a)9-3=6 ;  b)  6/7+5=6/7+35/7=41/7 ;

Explicație pas cu pas:

Answer 2

Răspuns:

$a) =6\\b) =\frac{410+410b}{7}$

Explicație pas cu pas:

$a) (3)*(3)-(3)=9-3=6$

$b) [(12):14+5][1+(?)][1-(3)][1-6]=\\\\(\frac{(12)}{14} +5)(1+b)(1-3)(1-6)=\\\\(\frac{6}{7} +\frac{35}{7} )(1+b)(-2)(-5)=\\\\(\frac{41}{7} )(1+b)(10)=\\\\\frac{41}{7} *(1+b)*10=\\\\\frac{10}{1}*\frac{41}{7} (1+b)=\\\\\frac{410}{7} *(1+b)=\\\\\frac{410}{7} *1+\frac{410}{7} b=\\\\\frac{410}{7} +\frac{410b}{7} =$

$\frac{410+410b}{7}$

Succes! :)