Question

9 Scrie sub forma de fractie ordinara ireductibila:
e)4(18)
f)0,(36)
g)1,(03)
h)2,(54)

Answer 1

e) 4, (18) = (418 - 4)/99 = 414/99 = 46/11
f) 0,(36) = 36/99 = 12/33 = 4/11
g) 1,(03) = (103 - 1)/99 = 102/99 = 34/33
h) 2,(54) = (254 - 2)/99 = 252/99 =  28/11