Question

(9 supra 37) totul la a 6 ×(37 supra 27) totul la a 6=​

Answer 1

Răspuns: $\red{\bf~3^{-6}=\dfrac{1}{3^{6}} ~}$

Explicație pas cu pas:

$\bf \bigg(\dfrac{9}{37}\bigg)^6\cdot \bigg(\dfrac{37}{27}\bigg)^6=\dfrac{9^6}{\not37^6}~\cdot~\dfrac{\not37^6}{27^6} =$

$\bf\dfrac{9^6}{27^6}=\dfrac{(3^2)^6}{(3^3)^6} =\dfrac{3^{2\cdot6}}{3^{3\cdot6}} =\dfrac{3^{12}}{3^{18}} =3^{12}:3^{18}=$

$\bf 3^{12-18}=\red{\boxed{\bf~3^{-6}=\dfrac{1}{3^{6}} ~}}$

==pav38==