Question

9(x+1) _> -7(x+2)

"_>" este mai mare sau egal



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Answer 1

9(x+1) ≥ -7(x+2)

⇔ 9x+9 ≥ -7x-14

⇔ 9x+7x ≥ -14-9

⇔ 16x ≥ -23

⇔ x ≥ -23/16

Answer 2

$9(x + 1) \geqslant - 7(x + 2) \\ 9x + 9 \geqslant - 7x - 14 \\ 9x + 7x \geqslant 9 + 14 \\ 16x \geqslant 23 \\ x \geqslant \frac{16}{23 } \\ x \geqslant 0.695 \\ x = (0.696. \infty )$